Question -
Answer -
Let us consider (a, 0) be the point on the x-axis that isequidistant from the point (7, 6) and (3, 4).
So,
Now, let us square on both the sides we get,
a2 – 14a + 85 = a2 – 6a + 25
-8a = -60
a = 60/8
= 15/2
∴ Therequired point is (15/2, 0)