The Total solution for NCERT class 6-12
a12┬а+ b12┬а= (a4)3┬а+(b4)3= (a4┬а+ b4) [(a4)2┬атАУa4b4┬а+ (b4)2]= (a4┬а+ b4) (a8┬атАУ a4b4┬а+b8)