The Total solution for NCERT class 6-12
125 + 8X3 – 27y3 + 90xy= (5)3 + (2x)3 + (-3y)3 – [3 x5 x 2x x (-3y)]= (5 + 2x – 3y) [(5)2 + (2x)2 + (-3y)2 –5 x 2x – 2x (-3y) – (-3y) x 5]= (5 + 2x – 3y) (25 + 4x2 + 9y2– 10x + 6xy + 15y)