The Total solution for NCERT class 6-12
We know thata3 + b3 + c3 – 3abc = (a + b +c) (a2 + b2 + c2 – ab – bc – ca)a3 + 8b3 + 64c3 – 24abc= (a)3 + (2b)3 + (4c)3 – 3 x ax 2b x 4c= (a + 2b + 4c) [(a)2 + (2b)2 + (4c)2 -ax 2b – 2b x 4c – 4c x a]= (a + 2b + 4c) (a2 + 4b2 + 16c2 –2ab – 8bc – 4ca)