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Question -

At any point (xy) of acurve, the slope of the tangent is twice the slope of the line segment joiningthe point of contact to the point (–4, –3). Find the equation of the curvegiven that it passes through (–2, 1).



Answer -

It is given that (xy)is the point of contact of the curve and its tangent.

The slope (m1) of the line segmentjoining (xy) and (–4, –3) is 

Weknow that the slope of the tangent to the curve is given by the relation,

Accordingto the given information:

Integratingboth sides, we get:

Thisis the general equation of the curve.

Itis given that it passes through point (–2, 1).

SubstitutingC = 1 in equation (1), we get:

y + 3 = (x + 4)2

Thisis the required equation of the curve.

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