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Question -

A satellite orbits the earth at a height of400 km above the surface. How much energy must be expended to rocket thesatellite out of the earth’s gravitational influence? Mass of the satellite =200 kg; mass of the earth = 6.0 ×1024 kg; radius of theearth = 6.4 ×106 m; G = 6.67 × 10–11 N m2 kg–2.



Answer -

Mass of the Earth, M = 6.0× 1024 kg

Mass of the satellite, m =200 kg

Radius of the Earth, Re = 6.4 × 106 m

Universal gravitational constant, G = 6.67 ×10–11 Nm2kg–2

Height of the satellite, h =400 km = 4 × 105 m = 0.4 ×106 m

Totalenergy of the satellite at height h
Orbital velocity of the satellite, v =
Total energy of height, h

The negative signindicates that the satellite is bound to the Earth. This is called bound energyof the satellite.

Energy required to sendthe satellite out of its orbit = – (Bound energy)

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