The Total solution for NCERT class 6-12
Suppose that the electric fieldamplitude of an electromagnetic wave is E0 = 120 N/C and thatits frequency is ν = 50.0 MHz.(a) Determine, B0, ω, k, and λ. (b) Find expressions for E and B.
Electric field amplitude, E0 = 120 N/C
Frequencyof source, ν = 50.0 MHz = 50 ×106 Hz
Speed oflight, c = 3 × 108 m/s
Angular frequency of source isgiven as:
ω = 2πν
= 2π × 50× 106
= 3.14 ×108 rad/s
Propagationconstant is given as:
Wavelength of wave is given as:
(b) Supposethe wave is propagating in the positive x direction.Then, the electric field vector will be in the positive y direction and the magnetic fieldvector will be in the positive z direction.This is because all three vectors are mutually perpendicular.
Equation of electric field vectoris given as:
And, magnetic field vector isgiven as: