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Question -

In the figure, it is given that AB = CD and AD = BC. Prove that ∆ADC ≅ ∆CBA.



Answer -

Given : In the figure, AB = CD, AD = BC
 
To prove : ∆ADC = ∆CBA
Proof : In ∆ADC and ∆CBA
CD = AB (Given)
AD = BC (Given)
CA = CA (Common)
∴ ∆ADC ≅ ∆CBA (SSS axiom)

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