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Chapter 13 Motion and Time Solutions

Question - 1 : -
Classify the following as motion along a straight line, circular or oscillatory motion :
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round. •
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.

Answer - 1 : -

(i) Oscillatory motion
(ii) Linear motion
(iii) Circular motion
(iv) Oscillatory motion
(v) Oscillatory motion
(vi) Linear motion

Question - 2 : -
Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometers.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h

Answer - 2 : - (ii), (iv), (v)

Question - 3 : - A simple pendulum takes 32s to complete 20 oscillations, what is the time period of the pendulum?

Answer - 3 : -

Time taken to complete 20 oscillations = 32 s
Time taken to complete 1 oscillation = 32/20 s = 1.6 s
Time period of a pendulum is time taken by it to complete 1 oscillation.
Time period of pendulum is 1.6 seconds.

Question - 4 : - The distance between two stations is 240 km. A train takes 4 hours to cover this distance. Calculate the speed of the train.

Answer - 4 : -

Distance = 240 km
Time taken = 4 hours
Speed =Distance covered/time taken = 240km/4 hammer
=60 km/h
Speed of train =60 km/h

Question - 5 : - The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.

Answer - 5 : -

Distance = 57336.0 km – 57321 km =15 km
Speed in km/min =15km/20 min = 3/4 km/min
Speed in km/hr =15 km/1/3 hr
=(15 x 3) km/hr
=45 km/hr.

Question - 6 : - Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/min, calculate the distance between her house and the school.

Answer - 6 : -

Time taken =15 min
Speed = 2 m/min .
Distance = speed x time = 2 x 15 = 30 m
Distance between Salma’s school and her house is 30 m.

Question - 7 : -
Show the shape of the distance-time graph for the motion in the following cases :
(i) A car moving with a constant speed.
(ii) A car parked on a side road

Answer - 7 : - (i) 


(ii)

Question - 8 : -
Which of the following relations is correct?
(i) Speed = Distance Time
(ii) Speed = Distance/Time
(iii)Speed – Time/Distance
(iv)Speed = 1/Distance Time

Answer - 8 : - (ii) Speed = Distance/Time is correct

Question - 9 : -
The basic unit of speed is:
(i) km/min              (ii) m/min 
(iii) km/h                (iv) m/s

Answer - 9 : - (iv) m/s

Question - 10 : -
A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
(i) 100 km               (ii) 25 km
(iii) 15 km                (iv) 10 km

Answer - 10 : - (ii) 25 km

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