Question -
Answer -
For region I (triangle),
Let a = 5 cm, b = 5 cm and c = 1 cm
Then, semi-perimeter of I triangle
Similarly area of region IV (right angled triangle )
= 4.5 cm2 [Since, it has same dimensions as region V]
∴ Total area of paper used = Area of region I + Area of region II + Area of region III +Area of region IV + Area of region V
= 2.49 + 6.5 +1. 30 + 4.5 + 4.5= 19.29 = 19.3 cm2 (approx.)