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Question -

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?



Answer -

If the number of animals increases, then it will take fewer days to last.
Then the two quantities are in inverse proportions.

Number of animals

Number of days

20

6

(20 + 10) or 30

P

Let the requirednumber of days be p.
x1y1 = x2y2
where x1 = 20, y1 = 6, x2 = 3
and y2 = p (let)
20 × 6 = 30 × p
p = 4
Hence the required number of days = 4.

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