Question -
Answer -
Given,
Diameter of a metallicball = 4.2 cm
Radius(r) of themetallic ball, r = 4.2/2 cm = 2.1 cm
Volume formula = 4/3πr3
Volume of the metallicball = (4/3)×(22/7)×2.1 cm3
Volume of the metallicball = 38.808 cm3
Now, usingrelationship between, density, mass and volume,
Density = Mass/Volume
Mass = Density ×volume
= (8.9×38.808) g
= 345.3912 g
Mass of the ball is 345.39g (approx).