The Total solution for NCERT class 6-12
(i) (y2 + 7y + 10) ÷ (y + 5)(ii) (m2 – 14m – 32) ÷ (m + 2)(iii) (5p2 – 25p + 20) ÷ (p – 1)(iv) 4yz(z2 + 6z – 16) ÷ 2y(z + 8)(v) 5pq(p2 – q2) ÷ 2p(p + q)(vi) 12xy(9x2 – 16y2) ÷ 4xy(3x + 4y)(vii) 39y3(50y2 – 98) ÷ 26y2(5y + 7)