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Question -

A class teacher hasthe following absentee record of 40 students of a class for the whole
term. Find the mean number of days a student was absent.



Answer -


Number of days

0-6

6-10

10-14

14-20

20-28

28-38

38-40

Number of students

11

10

7

4

4

3

1


Solution:

Find the midpoint of the given interval usingthe formula.

Midpoint (xi) = (upper limit +lower limit)/2

Class interval

Frequency (fi)

Mid-point (xi)

fixi

0-6

11

3

33

6-10

10

8

80

10-14

7

12

84

14-20

4

17

68

20-28

4

24

96

28-38

3

33

99

38-40

1

39

39

Sum fi = 40

Sum fixi = 499

The mean formula is,

Mean = x̄ = ∑fixi /∑fi

= 499/40

= 12.48 days

Therefore, the mean number of days a studentwas absent = 12.48.


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