Question -
Answer -
Given: Here from the question we get
(1) ABCD is a parallelogram
(2) P is any point in the interior of parallelogram ABCD
To prove:
Construction: Draw DN perpendicular to AB and PM perpendicular AB
Proof: Area of triangle =
× base× heightArea of
ÄAPB = .AB .PM …… (1)Also we know that: Area of parallelogram = base× height
Area of parallelogram ABCD = AB DN …… (2)
Now PM < DN (Since P is a point inside the parallelogram ABCD)
Hence it is proved that