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Question -

Solve each of the following system of equations in R.
x + 3 > 0, 2x < 14



Answer -

Given: x + 3 > 0 and 2x < 14
Let us consider the first inequality.
x + 3 > 0
x + 3 – 3 > 0 – 3
x > –3
Now, let us consider the second inequality.
2x < 14
Divide both the sides by 2 we get,
2x/2 < 14/2
x < 7
∴ The solution of the given system of inequation is (–3, 7).

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