Question -
Answer -
Given:
Sum of first threeterms is 24
Let us assume thefirst three terms are a тАУ d, a, a + d [where a is the first term and d is thecommon difference]
So, sum of first threeterms is a тАУ d + a + a + d = 24
3a = 24
a = 8
It is given that theproduct of three terms is 440
So a3┬атАУad2┬а= 440
Substitute the valueof a = 8, we get
83┬атАУ8d2┬а= 440
512 тАУ 8d2┬а=440
72 = 8d2
d = 3 or d = тАУ 3
Hence, the given termsare a тАУ d, a, a + d which is 5, 8, 11