Question -
Answer -
Given:
Sum of first threeterms is 24
Let us assume thefirst three terms are a – d, a, a + d [where a is the first term and d is thecommon difference]
So, sum of first threeterms is a – d + a + a + d = 24
3a = 24
a = 8
It is given that theproduct of three terms is 440
So a3 –ad2 = 440
Substitute the valueof a = 8, we get
83 –8d2 = 440
512 – 8d2 =440
72 = 8d2
d = 3 or d = – 3
Hence, the given termsare a – d, a, a + d which is 5, 8, 11