Question -
Answer -
Given: d = 10
We know that the sumof all angles in a quadrilateral is 360
Let us assume theangles are a – 3d, a – d, a + d, a + 3d
So, a – 2d + a – d + a+ d + a + 2d = 360
4a = 360
a = 90… (i)
And,
(a – d) – (a – 3d) =10
2d = 10
d = 10/2
= 5
Hence, the angles area – 3d, a – d, a + d, a + 3d which is 75o, 85o, 95o,105o