Question -
Answer -
Given:
Sum of first threeterms is 27
Let us assume thefirst three terms as a – d, a, a + d [where a is the first term and d is thecommon difference]
So, sum of first threeterms is
a – d + a + a + d = 27
3a = 27
a = 9
It is given that theproduct of three terms is 648
So, a3 –ad2 = 648
Substituting the valueof a = 9, we get
93 –9d2 = 648
729 – 9d2 =648
81 = 9d2
d = 3 or d = – 3
Hence, the given termsare a – d, a, a + d which is 6, 9, 12.