Question -
Answer -
Given:
(a/3 + 1, b – 2/3) = (5/3, 1/3)
By the definition of equality of ordered pairs,
Let us solve for a and b
a/3 + 1 = 5/3 and b – 2/3 = 1/3
a/3 = 5/3 – 1 and b = 1/3 + 2/3
a/3 = (5-3)/3 and b = (1+2)/3
a/3 = 2/3 and b = 3/3
a = 2(3)/3 and b = 1
a = 2 and b = 1
∴ Values of a and b are, a = 2 and b = 1
(ii) If (x + 1, 1) = (3y, y – 1), find the values of x and y.
Given:
(x + 1, 1) = (3y, y – 1)
By the definition of equality of ordered pairs,
Let us solve for x and y
x + 1 = 3y and 1 = y – 1
x = 3y – 1 and y = 1 + 1
x = 3y – 1 and y = 2
Since, y = 2 we can substitute in
x = 3y – 1
= 3(2) – 1
= 6 – 1
= 5
∴ Values of x and y are, x = 5 and y = 2