Question -
Answer -
Given:
The equation passesthrough (2,-1) and make an angle of 45° with the line 6x + 5y – 8 = 0
We know that theequations of two lines passing through a point x1, y1 andmaking an angle α with the given line y = mx + c are
Here, equation of thegiven line is,
6x + 5y – 8 = 0
5y = – 6x + 8
y = -6x/5 + 8/5
Comparing thisequation with y = mx + c
We get, m = -6/5
Where, x1 =2, y1 = – 1, α = 45°, m = -6/5
So, the equations ofthe required lines are
x + 11y + 9 = 0 and11x – y – 23 = 0
∴ The equation of givenline is x + 11y + 9 = 0 and 11x – y – 23 = 0