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Question -

Find the equations of straight lines passing through (2, -1) and making an angle of 45o with the line 6x + 5y тАУ 8 = 0.



Answer -

Given:

The equation passesthrough (2,-1) and make an angle of 45┬░ with the line┬а6x + 5y тАУ 8 = 0

We know that theequations of two lines passing through a point x1, y1┬аandmaking an angle┬а╬▒┬аwith the given line y = mx + c are

Here, equation of thegiven line is,

6x + 5y тАУ 8 = 0

5y = тАУ 6x + 8

y = -6x/5 + 8/5

Comparing thisequation with y = mx + c

We get, m = -6/5

Where, x1┬а=2, y1┬а= тАУ 1,┬а╬▒┬а= 45┬░, m = -6/5

So, the equations ofthe required lines are

x + 11y + 9 = 0 and11x тАУ y тАУ 23 = 0

тИ┤ The equation of givenline is┬аx + 11y + 9 = 0 and 11x тАУ y тАУ 23 = 0

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