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Question -

A circle whose centre is the point of intersection of the lines 2x – 3y + 4 = 0 and 3x + 4y – 5 = 0 passes through the origin. Find its equation.



Answer -

It is given that the circle has the centre at the intersection point ofthe lines 2x – 3y + 4 = 0 and 3x + 4y – 5 = 0 and passes through the origin

We know that theequation of the circle with centre (p, q) and having radius ‘r’ is given by: (x– p)2 + (y – q)2 = r2

Now by substitutingthe values in the equation, we get

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