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Question -

Organise the following marks in a class assessment, in a tabular form.
4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7
(i) Which number is the highest? (ii) Which number is the lowest?
(iii) What is the range of the data? (iv) Find the arithmetic mean.



Answer -

First, we have toarrange the given marks in ascending order.

= 1, 2, 2, 3, 4, 4, 4,5, 5, 5, 5, 5, 6, 6, 6, 6, 7, 7, 8, 9

Now, we will draw thefrequency table of the given data.

Marks

Tally Marks

Frequency

1

1

2

2

3

1

4

3

5

5

6

4

7

2

8

1

9

1

(i) By observing thetable clearly, the highest number among the given data is 9.

(ii) By observing thetable clearly, the lowest number among the given data is 1.

(iii) We know that,Range = Highest value – Lowest value

= 9 – 1

= 8

(iv) Now we have tocalculate Arithmetic Mean,

Arithmetic mean = (Sumof all observations)/ (Total number of observation)

Then,

Sum of all observation= 1 + 2 + 2 + 3 + 4 + 4 + 4 + 5 + 5 + 5 + 5 + 5 + 6 + 6 + 6 + 6 + 7 + 7

+ 8 + 9

= 100

Total Number of Observation= 20

Arithmetic mean =(100/20)

= 5

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