Question -
Answer -
Let us say, the average speed of passenger train =┬а x km/h.
Average speed of express train = (x + 11) km/h
Given, time taken by the express train to cover 132 km is 1 hour less than the passenger train to cover the same distance. Therefore,
(132/x) тАУ (132/(x+11)) = 1
132(x+11-x)/(x(x+11)) = 1
132 ├Ч 11 /(x(x+11)) = 1
тЗТ 132 ├Ч 11 =┬аx(x┬а+ 11)
тЗТ┬аx2┬а+ 11x┬атАУ 1452 = 0
тЗТ┬аx2┬а+┬а 44x┬а-33x┬а-1452= 0
тЗТ┬аx(x┬а+ 44) -33(x┬а+ 44) = 0
тЗТ (x┬а+ 44)(x┬атАУ 33) = 0
тЗТ┬аx┬а= тАУ 44, 33
As we know, Speed cannot be negative.
Therefore, the speed of the passenger trainwill be 33 km/h and thus, the speed of the express train will be 33 + 11 = 44km/h.