Question -
Answer -
(i) 2x2 – 7x +3 = 0
On comparing the given equation with ax2 + bx + c =0, we get,
a = 2, b = -7 and c =3
By using quadratic formula, we get,
⇒ x = (7±√(49 – 24))/4
⇒ x = (7±√25)/4
⇒ x = (7±5)/4
⇒ x = (7+5)/4 or x = (7-5)/4
⇒ x = 12/4 or 2/4
∴ x = 3 or 1/2
(ii) 2x2 + x –4 = 0
On comparing the given equation with ax2 + bx + c =0, we get,
a = 2, b = 1 and c = -4
By using quadratic formula, we get,
⇒x = -1±√1+32/4
⇒x = -1±√33/4
∴ x = -1+√33/4 or x = -1-√33/4
(iii) 4x2 + 4√3x +3 = 0
On comparing the given equation with ax2 + bx + c =0, we get
a = 4, b = 4√3 and c= 3
By using quadratic formula, we get,
⇒ x = -4√3±√48-48/8
⇒ x = -4√3±0/8
∴ x = -√3/2 or x = -√3/2
(iv) 2x2 + x +4 = 0
On comparing the given equation with ax2 + bx + c =0, we get,
a = 2, b = 1 and c =4
By using quadratic formula, we get
⇒ x = -1±√1-32/4
⇒ x = -1±√-31/4
As we know, the square of a number can neverbe negative. Therefore, there is no real solution for the given equation.