Question -
Answer -
Let us say, the shorter side of the rectangle be x m.
Then, larger side of the rectangle = (x + 30) m
As given, the length of the diagonal is = x +30 m
Therefore,
⇒ x2 + (x + 30)2 =(x + 60)2
⇒ x2 + x2 +900 + 60x = x2 + 3600 + 120x
⇒ x2 – 60x – 2700 = 0
⇒ x2 – 90x + 30x –2700 = 0
⇒ x(x – 90) + 30(x -90)= 0
⇒ (x – 90)(x + 30) = 0
⇒ x = 90, -30
However, side of the field cannot be negative.Therefore, the length of the shorter side will be 90 m.
and the length of the larger side will be (90+ 30) m = 120 m.