Question -
Answer -
Given quadratic equation,
x2┬а+ 3x┬а+ 5 = 0
On comparing it with┬аax2┬а+┬аbx┬а+┬аc┬а=0, we have
a┬а=1,┬аb┬а=3, and┬аc┬а=5
So, the discriminant of the given equation will be
D =┬аb2┬атАУ4ac┬а=32┬атАУ 4 ├Ч 1 ├Ч 5 =9 тАУ 20 = тАУ11
Hence, the required solutions are:
