The Total solution for NCERT class 6-12
(a – 2b)3 – 512b3= (a – 2b)3 – (8b)3= (a – 2b- 8b) [(a – 2b)2 + (a – 2b) x 8b + (8b)2]= (a – 10b) [a2 + 4b2 – 4ab + 8ab – 16b2 +64b2]= (a – 10b) (a2 + 4ab + 52b2)