The Total solution for NCERT class 6-12
8x3 + 27y3 – 216z3 +108xyz= (2x)3 + (3y)3 + (6z)3 – 3 x(2x) (3y) (-6z)= (2x + 3y – 6z) [(2x)2 + (3y)2 + (-6z)2 –2x x 3y – 3y x (-6z) – (-6z) x 2x]= (2x + 3y – 6z) (4x2 + 92 + 36z2 –6xy + 18yz + 12zx)