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Question -

Find the equation of the normal at the point(am2,┬аam3) for the curve┬аay2┬а=┬аx3.



Answer -

The equation of the given curve is┬аay2┬а=┬аx3.

On differentiating with respect to┬аx, wehave
The slope of a tangent to thecurve at (x0,┬аy0)is
┬аTheslope of the tangent to the given curve at (am2,┬аam3) is
тИ┤ Slope of normal at (am2,┬аam3)=┬а

Hence, the equation of the normal at (am2,┬аam3) isgiven by,

y┬атИТ┬аam3┬а=

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