The Total solution for NCERT class 6-12
If┬аf┬а(x) = 3x2┬а+15x┬а+ 5, then the approximate value of┬аf┬а(3.02) is
A.┬а47.66┬аB.┬а57.66┬аC.┬а67.66┬аD.┬а77.66
Let┬аx┬а= 3 and ╬Фx┬а=0.02. Then, we have:
Hence, the approximate value of┬аf(3.02)is 77.66.
The correct answer is D.