The Total solution for NCERT class 6-12
In the followingfigure, E is a point on side CB produced of an isosceles triangle ABC with AB =AC. If AD ⊥ BC and EF ⊥ AC, prove that ΔABD ~ ΔECF.
Solution:
Given, ABC is an isosceles triangle.∴ AB = AC⇒ ∠ABD = ∠ECFIn ΔABD and ΔECF,∠ADB = ∠EFC (Each 90°)∠BAD = ∠CEF (Already proved)∴ ΔABD ~ ΔECF (using AA similarity criterion)