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Question -

ABC is an isosceles triangle in which altitudes BE and CFare drawn to equal sides AC and AB respectively (see the given figure). Showthat these altitudes are equal.



Answer -

In ΔAEB and ΔAFC,

∠AEB and ∠AFC (Each 90º)

∠A = ∠A (Common angle)

AB = AC (Given)

∴ ΔAEB ≅ ΔAFC (By AAS congruence rule)

⇒ BE = CF (By CPCT)

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