MENU
Question -

In figure, rays OA,OB, OC, OD and OE have the common end point 0. Show that ∠AOB+∠BOC+∠COD+∠DOE+∠EOA=360°.



Answer -

Given: Rays OA, OB, OC, OD and OE have the common endpoint O.

Draw an opposite ray OX to ray OA, which make a straight lineAX.

From figure:

∠AOB and∠BOX arelinear pair angles, therefore,

∠AOB +∠BOX = 1800

Or, ∠AOB + ∠BOC + ∠COX = 1800 —–—–(1)

Also,

∠AOE and∠EOX arelinear pair angles, therefore,

∠AOE+∠EOX =180°

Or, ∠AOE + ∠DOE + ∠DOX = 1800 —–(2)

By adding equations, (1) and (2), we get;

∠AOB + ∠BOC + ∠COF + ∠AOE + ∠DOE + ∠DOX = 1800 + 1800

∠AOB + ∠BOC + ∠COD + ∠DOE + ∠EOA = 3600

Hence Proved.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×