The Total solution for NCERT class 6-12
an = a + nbLet n= 1, 2, 3, 4, 5, ……….a1 = a + ba2 = a + 2ba3 = a + 3ba4 = a + 4ba5 = a + 5bWe see that it is an A.P. whose common difference is b and a for any real valueof a and bas a2 – a1 = a + 2b – a – b = ba3 – a2 = a + 3b – a – 2b = ba4 – a3 = a + 4b – a – 3b = band a5 – a4 = a + 5b – a – 4b = b