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Question -

Find the equation of a curve passing throughthe point (0, –2) given that at any point (x, y) on the curve, the productof the slope of its tangent and y-coordinate of the point is equalto the x-coordinate of the point.



Answer -

Let and y bethe x-coordinate and y-coordinate of the curverespectively.

Weknow that the slope of a tangent to the curve in the coordinate axis is givenby the relation,

Accordingto the given information, we get:

Integratingboth sides, we get:

Now,the curve passes through point (0, –2).

(–2)2 – 02 = 2C

2C = 4

Substituting2C = 4 in equation (1), we get:

y2 – x2 = 4

Thisis the required equation of the curve.

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