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Question -

The 5th, 8th and 11th terms ofa G.P. are pq and s, respectively.Show that q2 = ps.



Answer -

Let’s take a tobe the first term and r to be the common ratio of the G.P.

Then according to thequestion, we have

a5 = a r5–1 a r4 = p …(i)

aa r8–1 a r7 = q …(ii)

a11 = a r11–1 a r10 = …(iii)

Dividing equation (ii)by (i), we get

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