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Question -

निम्नलिखित व्यंजकों के गुणनखण्ड कीजिए :
(i) 4a – 12
(ii) ac – be + c + cb
(iii) 36P +45 P
(iv) y_2 – 8ay
(v) 7a +7b
(vi) 3a_3x – 45a_2x – 18a



Answer -

(i) 4a – 12
हल :
4a – 12
= 4 (a-3)

(ii) ac – be + c + cb
हल :
ac – bc + c + cb
= (a – b + c + b)
= c (a + c)

(iii) 36P +45 P
हल :
36P + 45P3
(4 + 5P2)

(iv) y2 –8ay
हल :
y2 – 8ay = 9P
= y(y – 8a)

(v) 7a +7b
हल :
7a + 7b
= 7(a + b)

(vi) 3a3x –45a2x – 18a
हल :
3a3x – 45a2x –18a
= 3a(a – 15ax – 6)

 

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