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Question -

An antifreeze solution isprepared from 222.6 g of ethylene glycol (C2H6O2)and 200 g of water. Calculate the molality of the solution. If the density ofthe solution is 1.072 g mL−1, then what shall be the molarity of thesolution?



Answer -

Molar mass of ethylene glycol= 2 × 12 + 6 × 1 + 2 ×16

= 62 gmol−1

Numberof moles of ethylene glycol
= 3.59 mol
Therefore,molality of the solution = 17.95 m

Total mass of the solution =(222.6 + 200) g

= 422.6 g

Given,

Density of the solution = 1.072 gmL−1

Volume of the solution

= 394.22 mL

= 0.3942 × 10−3 L

 Molarity of thesolution 

= 9.11 M

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