Question -
Answer -
K+/K = тИТ2.93V, Ag+/Ag= 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = тИТ2.37 V, Cr3+/Cr= тИТ 0.74V
Arrangethese metals in their increasing order of reducing power.
Answer
The lower the reductionpotential, the higher is the reducing power. The given standard electrodepotentials increase in the order of K+/K < Mg2+/Mg< Cr3+/Cr < Hg2+/Hg < Ag+/Ag.
Hence, the reducing power of thegiven metals increases in the following order:
Ag < Hg < Cr < Mg < K