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Question -

How do you explain the absence of aldehyde group in thepentaacetate of D-glucose?



Answer -

D-glucose reacts with hydroxylamine (NH2OH)to form an oxime because of the presence of aldehydic (−CHO) group or carbonylcarbon. This happens as the cyclic structure of glucose forms an open chainstructure in an aqueous medium, which then reacts with NH2OHto give an oxime.

But pentaacetate of D-glucose does not reactwith NH2OH. This is because pentaacetate does not form an openchain structure.

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