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Question -

A bar magnet of magneticmoment 1.5 J T−1 lies aligned with the direction of a uniformmagnetic field of 0.22 T.

(a) What is the amountof work required by an external torque to turn the magnet so as to align itsmagnetic moment: (i) normal to the field direction, (ii) opposite to the fielddirection?

(b) What is the torqueon the magnet in cases (i) and (ii)?



Answer -

(a)Magnetic moment, M =1.5 J T−1

Magneticfield strength, B = 0.22 T

(i)Initial angle betweenthe axis and the magnetic field, θ1 = 0°

Final angle between theaxis and the magnetic field, θ2 = 90°

The work required tomake the magnetic moment normal to the direction of magnetic field is given as:

(ii) Initial anglebetween the axis and the magnetic field, θ1 = 0°

Final angle between theaxis and the magnetic field, θ2 = 180°

The work required tomake the magnetic moment opposite to the direction of magnetic field is givenas:

(b)For case (i): 

Torque, 

For case (ii): 

Torque, 

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