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Question -

A magnetic needle freeto rotate in a vertical plane parallel to the magnetic meridian has itsnorth tip pointing down at 22º with the horizontal. The horizontal component ofthe earth’s magnetic field at the place is known to be 0.35 G. Determine themagnitude of the earth’s magnetic field at the place.



Answer -

Horizontal component ofearth’s magnetic field, BH = 0.35 G

Angle made by the needlewith the horizontal plane = Angle of dip = 

Earth’s magneticfield strength = B

We can relate and BHas:

Hence, the strength ofearth’s magnetic field at the given location is 0.377 G.

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