The Total solution for NCERT class 6-12
A short bar magnetplaced with its axis at 30º with a uniform external magnetic field of 0.25T experiences a torque of magnitude equal to 4.5 × 10−2 J.What is the magnitude of magnetic moment of the magnet?
Magnetic fieldstrength, B = 0.25 T
Torque on the barmagnet, T = 4.5 × 10−2 J
Angle between the barmagnet and the external magnetic field,θ = 30°
Torque is related tomagnetic moment (M) as:
T = MB sin θ
Hence, the magneticmoment of the magnet is 0.36 J T−1.