MENU
Question -

The number of silicon atoms per m3 is 5 × 1028. Thisis doped simultaneously with 5 × 1022 atomsper m3 of Arsenic and 5 × 1020 perm3 atoms of Indium. Calculate the number ofelectrons and holes. Given that ni= 1.5 × 1016 m−3. Is thematerial n-type or p-type?



Answer -

Number of silicon atoms, N =5 × 1028 atoms/m3

Number of arsenic atoms, nAs =5 × 1022 atoms/m3

Number of indium atoms, nIn =5 × 1020 atoms/m3

Number of thermally-generated electrons, ni =1.5 × 1016 electrons/m3

Number of electrons, ne = 5 × 1022 − 1.5 × 1016 ≈4.99 × 1022

Number of holes = nh

In thermalequilibrium, the concentrations of electrons and holes in a semiconductor arerelated as:

nenh = ni2

Therefore, the number of electrons isapproximately 4.99 × 1022 and the number of holes is about 4.51 × 109. Since the number of electrons is more than thenumber of holes, the material is an n-type semiconductor.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×