Question -
Answer -
(a) A actsas the two inputs of the NOR gate and Y is the output, as shown inthe following figure. Hence, the output of the circuit is
The truth table for the same is given as:
| A | Y |
| 0 | 1 |
| 1 | 0 |
This is the truth table of a NOT gate. Hence, this circuitfunctions as a NOT gate.
(b) A and B arethe inputs and Y isthe output of the given circuit. By using the result obtained in solution (a), we can infer that the outputs ofthe first two NOR gates are
as shown in the followingfigure.
are the inputs for the last NOR gate. Hence, the outputfor the circuit can be written as:
The truth table for the same can be written as:
| A | B | Y (=A⋅B) |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
This is the truth table of an AND gate. Hence, thiscircuit functions as an AND gate.